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em4x70 makestyle

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This commit is contained in:
Christian Molson 2020-12-12 10:02:43 -05:00
commit 701914430f
2 changed files with 11 additions and 11 deletions
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16
armsrc/em4x70.c
View file

@ -365,31 +365,31 @@ static int authenticate(const uint8_t *rnd, const uint8_t *frnd, uint8_t *respon
if (find_listen_window(true)) {
em4x70_send_nibble(EM4X70_COMMAND_AUTH, true);
// Send 56-bit Random number
for(int i=0;i<7;i++) {
for (int i = 0; i < 7; i++) {
em4x70_send_byte(rnd[i]);
}
// Send 7 x 0's (Diversity bits)
for(int i=0; i<7; i++) {
for (int i = 0; i < 7; i++) {
em4x70_send_bit(0);
}
// Send 28-bit f(RN)
// Send first 24 bits
for(int i=0; i < 3; i++) {
for (int i = 0; i < 3; i++) {
em4x70_send_byte(frnd[i]);
}
// Send last 4 bits (no parity)
em4x70_send_nibble((frnd[3] >> 4) & 0xf, false);
// Receive header, 20-bit g(RN), LIW
uint8_t grnd[EM4X70_MAX_RECEIVE_LENGTH] = {0};
int num = em4x70_receive(grnd);
if(num < 10) {
if (num < 10) {
Dbprintf("Auth failed");
return PM3_ESOFT;
}

6
client/src/cmdlfem4x70.c
View file

@ -253,7 +253,7 @@ int CmdEM4x70Auth(const char *Cmd) {
"Authenticate against an EM4x70 by sending random number (RN) and F(RN)\n"
" If F(RN) is incorrect based on the tag crypt key, the tag will not respond",
"lf em 4x70 auth -r 11223344556677 -f 11223344\n"
);
);
void *argtable[] = {
arg_param_begin,
@ -264,9 +264,9 @@ int CmdEM4x70Auth(const char *Cmd) {
};
CLIExecWithReturn(ctx, Cmd, argtable, true);
etd.parity = arg_get_lit(ctx, 1);
int rnd_len = 7;
CLIGetHexWithReturn(ctx, 2, etd.rnd, &rnd_len);